Hello there ..i already do lab for mpich2 and connect all computers i have and i do cpi program and its work correctly .. but when i execute my program its give a message : the process stop working because one process exiting without calling MPI_Init .. what i can do to make it works.. ?? On Wednesday, December 10, 2014 4:33 PM, Rolf Rabenseifner <[email protected]> wrote: Dear Mr. Hehn, as long as you start your example with exactly two MPI processes, your example is guaranteed to run without deadlock based on the wording on nonblocking progress MPI-3.0 page 56, lines 30-35. Therefore, it is still deadlock-free if you Substitute your
MPI_Waitall(2,r,s);
by MPI_Wait(&r[0],s[0]); MPI_Wait(&r[1],s[1]); Thank you for your request on whether the MPI standard is completely describing the nonblocking functionality. Best regards Rolf ----- Original Message -----
From: "Andreas Hehn" <[email protected]> To: [email protected] Sent: Wednesday, December 10, 2014 12:15:28 PM Subject: [Mpi-comments] non-blocking communication deadlock possible?
Dear MPI comments readers,
I am not 100% sure if the following piece of code could cause a deadlock in a standard-compliant MPI implementation or not.
#include <mpi.h>
int main(int argc, char** argv) { MPI_Status s[2]; int num;
MPI_Init(&argc, &argv); MPI_Comm_rank(MPI_COMM_WORLD,&num);
double ds=5.4; // to send double dr; // to receive int tag=99;
MPI_Request r[2]; if(num==0) { MPI_Isend(&ds,1,MPI_DOUBLE,1,tag,MPI_COMM_WORLD,&r[0]); MPI_Irecv (&dr,1,MPI_DOUBLE,1,tag,MPI_COMM_WORLD,&r[1]); } else { MPI_Isend(&ds,1,MPI_DOUBLE,0,tag,MPI_COMM_WORLD,&r[0]); MPI_Irecv (&dr,1,MPI_DOUBLE,0,tag,MPI_COMM_WORLD,&r[1]); }
MPI_Waitall(2,r,s);
MPI_Finalize(); return 0; }
It is not entirely clear to me if the order of MPI_Isend and MPI_Irecv matters (as it does for blocking communication). Both function calls should return immediately according to section 3.7 of the standard - even if MPI_Isend uses synchronous send. So at this point there shouldn't be any problem. However, will MPI_Waitall() return for any order of the filed requests? The standard says it is equivalent to MPI_Wait() for the number of requests in "some arbitrary order" (line 28 of page 59). I suppose this means MPI_Waitall() is not supposed to mind the order of the requests in any way. Therefore it could not deadlock. Is this correct and is the line of argument sufficient to exclude the possibility of a deadlock?
Best regards,
Andreas Hehn _______________________________________________ mpi-comments mailing list [email protected] http://lists.mpi-forum.org/mailman/listinfo.cgi/mpi-comments
-- Dr. Rolf Rabenseifner . . . . . . . . . .. email [email protected] High Performance Computing Center (HLRS) . phone ++49(0)711/685-65530 University of Stuttgart . . . . . . . . .. fax ++49(0)711 / 685-65832 Head of Dpmt Parallel Computing . . . www.hlrs.de/people/rabenseifner Nobelstr. 19, D-70550 Stuttgart, Germany . . . . (Office: Room 1.307) _______________________________________________ mpi-comments mailing list [email protected] http://lists.mpi-forum.org/mailman/listinfo.cgi/mpi-comments