The MPI standard is pretty clear about this. 1) MPI_Type_create is a local function, each process is freely allowed to call it with it's arguments. 2) the matching in MPI must have the same type signature (and not type map), thus the local displacement on the datatype is not significant. Feel free to read the Datatype chapter in MPI 3.0 for further information. George. On Jul 18, 2013, at 14:11 , Minh Quan HO <[email protected]> wrote:

Hello, I'm working on HPL (High Performance Linpack) and I have a question about MPI_Type_create_struct :

int MPI_Type_struct( int count, int *array_of_blocklengths, MPI_Aint *array_of_displacements, MPI_Datatype *array_of_types, MPI_Datatype *newtype )

- Two processes A and B calls MPI_Type_create_struct with the same content of 'count', 'array_of_blocklengths' and 'array_of_types', but maybe *not* the same 'array_of_displacements' (due to private memory or custom stride of send/recv buffer)

- Example : On process A : count = 3 dispA[0] = 0 - blen[0] = 1 - type[0] = MPI_INT => block0 dispA[1] = 16 - blen[1] = 2 - type[1] = MPI_DOUBLE => block1 dispA[2] = 2014 - blen[2] = 4 - type[2] = MPI_DOUBLE => block2

On process B : count = 3 dispB[0] = 8 - blen[0] = 1 - type[0] = MPI_INT dispB[1] = 24 - blen[1] = 2 - type[1] = MPI_DOUBLE dispB[2] = 128 - blen[2] = 4 - type[2] = MPI_DOUBLE

- The question is : According to MPI, is this possible that two processes calls this MPI routine with their own different displacements ? (like example above - and also what HPL does)

- If yes, at Receiver side, I suppose that further send/recv with this type will do : block0 from A at dispA[0] must be written to B on dispB[0] block1 from A at dispA[1] must be written to B on dispB[1] and block2 from A at dispA[2] must be written to B on dispB[2], aren't they ?

Thank you for any response,

Quan _______________________________________________ mpi-forum mailing list [email protected] http://lists.mpi-forum.org/mailman/listinfo.cgi/mpi-forum